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In the dissociation of HI, 20% of HI is ...

In the dissociation of HI, `20%` of HI is dissociated at equilibrium. Calculate `K_(p)` for
`HI(g) hArr 1//2 H_(2)(g)+1//2 I_(2)(g)`

Text Solution

Verified by Experts

The correct Answer is:
`K_(p) = K_(c)= 0.125`
` {:(,HI,hArr,1/2H^(2),+,1/2I_(2)),("Initial",1 "mole",,0,,0),(" AT. eqm.",1-0*20=0*80 " mole",,0*10 " mole",,0*10 " mole"):}`
`K_(c) = ((0*1)^(1//2)(0*1)^(1//2))/(0*80)=0*125, K_(p)=K_(c) = 0*055`
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