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At 448^(@)C, the equilibrium constant (K...

At `448^(@)C`, the equilibrium constant `(K_(c))` for the reaction
`H_(2)(g)+I_(2)(g) hArr 2HI(g)`
is `50.5`. Presict the direction in which the reaction will proceed to reach equilibrium at `448^(@)C`, if we start with `2.0xx10^(-2)` mol of HI, `1.0xx10^(-2)` mol of `H_(2)` and `3.0xx10^(-2)` mol of `I_(2)` in a `2.0 L` constainer.

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Verified by Experts

The correct Answer is:
Forward direction
Q comes out to be `1*3` which is less than K .
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