Write the expression for the equilibrium constant `K_(c )` for each of the following reactions:
a. `2NOCl(g) hArr 2NO(g)+Cl_(2)(g)`
b. `2Cu(NO_(3))_(2)(s) hArr 2CuO(s)+4NO_(2)(g)+O_(2)(g)`
c. `CH_(3)COOC_(2)H_(5)(aq)+H_(2)O(1) hArr CH_(3)COOH(aq)+C_(2)H_(5)OH(aq)`
d. `Fe^(3+)(aq)+3OH^(Θ)(aq) hArr Fe(OH)_(3)(s)`
e. `I_(2)(s)+5F_(2) hArr 2IF_(5)`

Explanation

`K_(c) = ([NO(g)]^(2) [Cl_(2) (g) ])/([NOCl(g) ]^(2))`
` K_(c) = ([CuO(s)]^(2) [NO_(2) (g)]^(4) [O_(2)(g)])/([Cu (NO_(3))_(2) (s)]^(2))= [NO_(2)(g)]^(4) [O_(2)(g)]`
`K_(c) = ([CH_(3) COOH (aq)] [C_(2)H_(5)OH(aq)])/([CH_(3) COOC_(2) H_(5) (aq) ] [H_(2)O(l) ])`
` K_(c) = [Fe(OH)_(3)(s)]/([Fe^(3+) (aq) ][OH^(-)(aq)]^(3) )= 1/([Fe^(3) (aq) ][OH^(-)(aq)]^(3)) " "(v)K_(c) = ([IF_(5)]^(2))/[I_(2) (s) [F_(2)]^(5))= ([IF_(5)]^(2))/([F_(2)]^(5))`