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Find out the value of K(c ) for each of ...

Find out the value of `K_(c )` for each of the following equilibrium from the value of `K_(p)`:
a. `2NOCl(g) hArr 2NO(g)+Cl_(2)(g), K_(p)=1.8xx10^(-2)` at `500 K`
b. `CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(p)=167` at `1073 K`

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(a) ` Delta n_(g) = 3-2 =1 K_(p) = K_(c) (RT) or K_(c) =(K_(p))/(RT) = (1*8 xx 10^(-2))/(0*0831 xx 500) " " (R = 0*0831 "bar litre mol"^(-1) K^(-1))`
` = 4* 33 xx 10^(-4) `
(b) ` Delta n_(g) = 1 - 0 = 1 , K_(c) = (K_(p))/ (RT) = (167)/(6*3 xx 10^(14))= 1*87 .`
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Find out the value of K_(c) for each of the following equilibrium from the value of K_(p) : ( a ) 2NOCl_((g))hArr2NO_((g))+Cl_(2(g)) , ( K_(p)=1.8xx10^(-2)atm at 500 K ) ( b ) CaCO_(3(s))hArrCaO_((s))+CO_(2(g)) , ( K_(p)=167 atm at 1073 K )

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