A sample of `HI(g)` is placed in flask at a pressure of `0.2 atm`. At equilibrium. The partial pressure of `HI(g)` is `0.04 atm`. What is `K_(p)` for the given equilibrium?
`2HI(g) hArr H_(2)(g)+I_(2)(g)`

Explanation

` {:(,2 HI(g),hArr,H_(2)(g),+,I_(2)), (" Intial pressure",0*2"atm",,0,,0), ("At eqm",0*04,,(0*16)/2,,(0*16)/2),(,,,=0*8"atm",,=0*8 "atm"),(,,,,,("Decease in the pressure pf Hi" = 0*2 - 0*04 = 0*16 "atm")):}`
` :. K_(p) = ( pH_(2) xx pI_(2))/(p_(HI_(2))) = ( 0*8 "atm " xx 0*08 "atm")/(0*04 "atm")^(2)= 4*0 . `