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Equilibrium constant, K(c) " for the rea...

Equilibrium constant, `K_(c) " for the reaction" , N_(2) (g) + 3 H_(2) (g) hArr 2 NH_(3) (g) " at " 500 K " is " 0*061.` At a particular time, the analysis shows that composition of the reaction mixture is `3*0" mol "L^(-1) N_(2), 2*0 " mol "L^(-1) H_(2) and 5*0 "mol " L^(-1) NH_(3). ` Is the reaction at equilibrium ? If not , in which direction does the reaction tend to reach equilibrium ?

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To determine whether the reaction is at equilibrium and in which direction it tends to move, we can follow these steps: ### Step 1: Write the balanced chemical equation The balanced chemical equation for the reaction is: \[ \text{N}_2(g) + 3 \text{H}_2(g) \rightleftharpoons 2 \text{NH}_3(g) \] ### Step 2: Write the expression for the equilibrium constant \( K_c \) The equilibrium constant \( K_c \) for the reaction is given by the formula: ...
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Equilibrium constant, K_(c) for the reaction, N_(2(g))+3H_(2(g))hArr2NH_(3(g)) , at 500 K is 0.061 litre^(2) "mole"^(-2) . At a particular time, the analysis shows that composition of the reaction mixture is 3.00 mol litre^(-1)N_(2) , 2.00 mol litre^(-1)H_(2) , and 0.500 mol litre^(-1)NH_(3) . Is the reaction at equilibrium? If not, in which direction does the reaction tend to proceed to reach equilibrium?

At 773 K, the equilibrium constant K_(c) for the reaction, N_(2) (g) + 3 H_(2) (g) hArr 2 NH_(3) (g)" is " 6.02 xx 10^(-2)L^(2) mol^(-2). Calculate the value of K_(p) at the same temperature.

For the reaction N_(2) (g) + 3 H_(2) (g) hArr 2 NH_(3) (g) " at " 400 K , K_(p) = 41 Find the value of K_(p) for the following reaction : 1/2 N_(2) (g) + 3/2 H_(2) hArr NH_(3) (g)

At 800 K, the equilibrium constant for the reaction, N_2(g) + 3H_2(g) hArr 2NH_3(g) is 6.05xx10^(-2)L^2 "mol"^(-2) . Calculate K_p for the reaction at the same temperature.

For gaseous reaction N_2(g) +3H_2(g) hArr 2NH_3(g) , the units of equilibrium constant K_p are ………..

At 500^(@)C the equilibrium constant for the reaction N_(2)(g) + 3H_(2) (g) hArr 2NH_(3)(g) is 6.02 xx 10^(-2) litre^(-2) mol^(-2) What is the value of K_(p) at the same temperature?

The equilibrium constant for the reaction : N_2(g)+3H_2(g) hArr 2NH_3(g) at 715 K is 6.0xx10^(-2) If in a particular reaction , there are 0.25 mol L^(-1) of H_2 and 0.06 mol L^(-1) of NH_3 present at equilibrium , calculate the concentration of N_2 at equilibrium.

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