Dihydrogen gas used in Haber's process is produced by reacting methane from natural gas with high temperature steam. The first stage of the two `2` stage reaction involves the formation of `CO` and `H_(2)`. In second stage, `CO` formed in first stage is reacted with more steam in water gas shift reaction,
`CO(g)+H_(2)O(g) hArr CO_(2)(g)+H_(2)(g)`
If a reaction vessel at `400^(@)C` is charged with an equimolar mixture of `CO` and steam such that `p_(CO)=p_(H_(2)O)=4.0` bar, what will be the partial pressure of `H_(2)` at equilibrium? `K_(p)=0.1` at `400^(@)C`.

Explanation

`{:(,CO(g) ,+,H_(2)O (g),hArr,CO_(2)(g),+,H_(2)(g)),("Intial pressure",4*0 "bar",,4*0 "bar",,,,),("At eqm.",(4-p),,(4-p),,p,,p):}`
` K_(p) = (p^(2))/(4-p)^(2) = 0*1 ("Given") :. p/(4-p) = sqrt (0*1) = 0*316 `
` p= 1*264 - 0*316 p or 1* 316 p = 1* 264 or p = 9*96 "bar". " Hence, " (p_(H_(2))) _(eqm.) = 0*96 "bar" `