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The value of K(c) " for the reaction , ...

The value of ` K_(c) " for the reaction , " 3 O_(2) (g) hArr 2 O_(3) (g) , "is " 2*0 xx 10^(-50) " at " 25^(@)C. " If the equilibrium concentration of " O_(2) " in air at " 25^(@)C " is " 1*6 xx 10^(-2), " What is the concentration of " O_(3) ? `

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Verified by Experts

` K_(c) = ([CH_(4)] [H_(2)O])/([CO][H_(2)]^(3))`
` :. 3 * 90 = (([CH_(4)] (0*02)])/(( 0*30)(0*10)^(3)) " " ( "Molar conc = No. of moles because volume of flask = 1 L")`
or `[CH_(4)]= 0*0585 "M" = 5 * 85 xx 10^(-2) "M" `
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