The equilibrium constant of a reaction is ` 2 xx 10^(-3) " at " 25^(@)C and 2xx10^(-2) " at " 50^(@)C.` Is the reaction exothermic or endothermic ?

Explanation

To determine whether the reaction is exothermic or endothermic based on the given equilibrium constants at two different temperatures, we can follow these steps:

### Step 1: Write down the given data
- Equilibrium constant (Kc) at 25°C = \(2 \times 10^{-3}\)
- Equilibrium constant (Kc) at 50°C = \(2 \times 10^{-2}\)

### Step 2: Analyze the change in equilibrium constant with temperature
We observe that as the temperature increases from 25°C to 50°C, the equilibrium constant (Kc) increases from \(2 \times 10^{-3}\) to \(2 \times 10^{-2}\).
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