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When sulphur in the form of S(8) is heat...

When sulphur in the form of `S_(8)` is heated at `900 K`, the initial pressure of `1` atm falls by `10%` at equilibrium. This is because of conversion of some `S_(8)` to `S_(2)`. Find the value of equilibrium constant for this reaction.

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` {:(,S_g(g),hArr,4S_(2)(g)), (" Intial",1 atm,,), (" At eqm.",1-0*29 = 0*71 "atm",,4b xx 0*29 "atm" = 1*16 "atm"):} `
` K_(p) = (p_(s_(2)(g))^(4))/(p_(s_(g(g))))= (1*16 " atm ")^(4)/(0*71 "atm" )=2*55 " atm "^(3)`
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