At `540 K, 0.10 mol` of `PCl_(5)` is heated in a `8L` flask. The pressure of equilibrium mixture is found to be `1.0 atm`. Calculate `K_(p)` and `K_(c )` for the reaction.

Explanation

` {: (,PCl_(5),hArr,PCl_(3) ,+,Cl_(2),), (" Intial" ,0*1 "mol",,,,,),("At eqm.",0*1-x,,x,,x,"Total no. of moles at eqm . "= 0*1+x):}`
` PV = nRT , i.e., n=(PV)/(RT)= (1xx8)/(0*0821 xx540 )= 0*18`
` :. 0*1 + x 0*18 or x = 0*08 :. K_(c) = ((0*08 //8) (0*08//8))/(0*02 //8) = 0*04`
` K_(p) = K_(c) (RT)^(Delta n )= 0*04 (0*821 xx 540 )^(1) = 1*77 `