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For the reaction CaCO(3) (s) hArr CaO (s...

For the reaction `CaCO_(3) (s) hArr CaO (s) + CO_(2) (g), K_(p) = 1*16 " atm . If "20* 0" g of " CaCO_(3) " is heated to " 800^(@)C" in a 10 litre container, what % of "CaCO_(3) " would remain unreached at equilibrium ? ( Mol. wt. of " CaCO_(3) = 100, R = 0*0821 " L atm mol"^(-1) K^(-1) )`

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(i) `20*0 g CaCO_(3) = (20*0)/(100) = 0*2 "mol" `
` {:(,CaCO_(3)(s),hArr,CaO(s),+,CO_(2)(g)), ("Intial",0*2"mol",,0,,0), ("At eqm." ,(0*2-x) "mol" ,,x "mol",,x "mol") :}`
But for the given equilibrium , `K_(p) = p_(CO_(2)) . " Hence , " p_(CO_(2))= 1*16 "atm " `
Now, ` n = (PV)/(RT) :. x " mol of " CO_(2) = (1*16 xx 10)/(0*0821 xx 1073)=0*13 "mol" `
` :. " Unreacted " CaCO_(3) = (0*2 - 0*13 ) "mol" = 0*07 "mol" = 0*07 xx 100 g = 7 g `
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