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500 ml vessel contains 1.5 M each of A, ...

500 ml vessel contains 1.5 M each of A, B, C and D at equlibrium. If 0.5 M each of C and D are taken out, the value of `K_(c)` for `A+BhArrC+D` will be

A

`1.0`

B

`1//9`

C

`4//9`

D

`8//9`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(c) = ( 1.5 xx 1.5)/(1.5 xx 1.5) = 1 .` On changing concentrations , equilibrium constant does not change .
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