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NH(4)COONH(2)(s)hArr2NH(3)(g)+CO(2)(g) I...

`NH_(4)COONH_(2)(s)hArr2NH_(3)(g)+CO_(2)(g)` If equilibrium pressure is 3 atm for the above reaction, then `K_(p)` for the reaction is

A

4

B

27

C

`4//27`

D

`1//27`

Text Solution

Verified by Experts

The correct Answer is:
A

Suppose at equilibrium , `p_(CO_(2)=p " atm " ` Then `p_(NH_(3) = 2 " p "atm` We are given that
`p+2 p = 3 atm :. P=1 atm` ,
i.e., ` p_(CO_(2) )= 1 " atm " and p_(NH_(3))= 2 " atm "`
Hence , ` K_(p) = p_(NH_(3))^(2) xxp_(CO_(2)) = (2)^(2) xx 1 4. `
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