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The equilibrium pressure for the reactio...

The equilibrium pressure for the reaction ` MSO_(4).2H_(2)O (s) hArr MSO_(4) (s) + 2H_(2)O (g) " is " pi //4 "atm at 400 K . The " K_(p) " for the given reaction ( in " atm^(2) ) ` is

A

`pi^(2)//4`

B

`pi//6`

C

`pi^(2)//16`

D

`pi/16`

Text Solution

Verified by Experts

The correct Answer is:
C

For the given heteobeneous equilibrium
` K_(p) = p_(H_(2)O)^(2) = (pi/4)^(2) = pi^(2)/16`
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