For the reaction
`H_(2)(g)+CO(g)hArrCO(g)+H_(2)O(g),` if the initial concentration of`[H_(2)]=[CO_(2)]`and x moles /litres of hydrogen is consummed at equilibrium , the correct expression of `K_(p)` is :

Options

A. `x^(2)/(1-x)^(2)`
B. ` (1+x)^(2)/(1-x)^(2)`
C. `x^(2)/(2+x)^(2)`
D. `x^(2)/(1-x)^(2)`

Answer

A

Explanation

` {:(,H_(2)(g),+,CO_(2) (g),hArr,CO (g),+,H_(2)O(g)), ("Intial ",1,,1,,0,,0), ("At . eqm.",1-x,,1-x,,x,,x):}`
` K_(c) = (x xx x)/((1-x)(1-x))=x^(2)/(1-x)^(2)`.
`K_(p)= K_(c)" " ( :' Delta n_(g)= 0)`