Consider thr reaction where `K_(p)=0.497 `at 500K
`PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)`
If the htree gasses are mixed in a right container so that the partial pressure of each gas in initially 1 atm ,then which is correct observation ?

Options

A. More `PCl_(5)` will be produced
B. More `PCl_(3)` will be produced
C. Equilibrium will be established when 50% of the reaction is complete
D. None of the above

Answer

A

Explanation

`Q_(p) = (p_(PCl_(3))xxp_(Cl_(2)))/(p_(PCl_(5)))=(1 atm xx1 atm )/(1atm )=1`
As `Q_(p) gt K_(c)` , equilibrium will go in the backward direction , i.e., more `PCl_(5)` will be produced .