For the reaction, `AB(g)hArr A(g)+B(g), AB" is "33%` dissociated at a total pressure of 'p' Therefore, 'p' is related to `K_(p)` by one of the following options

Options

A. `P=K_(p)`
B. ` P=3 K_(p)`
C. ` P=4K_(p)`
D. ` P=8 K_(p)`

Answer

D

Explanation

`{:(,AB (g),hArr,A(g),+,B(g)),("Intial moles:",1,,0,,0),("Moles at eqm:",1-0.33,,0.33,,0.33):}`
`0.67`
Total moles at eqm. =1.33
`p_(A) =(0.33/1.33)P, p_(B)=(0.33/1.33) P,p_(AB)=(0.67/1.33)P`
`K_(p) = (p_(A) xxp_(B))/p_(AB) = (0.33 xx 0.33 xx P)/(0.67 xx 1.33)`
`P/K_(p)=8 or P =8 K_(p).`