A vessel at 1000 K contains `CO_2` with a pressure of 0.5 atm. Some of the `CO_2` is converted to CO on addition of graphite. Calculate the value of K, if the total pressure at equilibrium is 0.8 atm.

Options

A. 3 atm
B. `0*3 `atm
C. `0*18 atm`
D. `1*8 ` atm

Answer

D

Explanation

`{:(,CO_(2)(g),+,C(s),hArr,2CO(g)),(" Intial ",0.5 atm,,,,),("At eqm.",0.5 -p,,,,2 p):}`
`:. (0.5 -p) +2 p = 0.8" atm " or p=0.3 " atm "`
`K=(p^(2) CO)/p_(CO_(2)) = (0.6)^(2)/((0.5 -0.3)) = (0.6 xx0.6)/0.2 = 1.8 " atm", `