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For the reaction C(s) +CO(2)(g) rarr 2CO...

For the reaction `C(s) +CO_(2)(g) rarr 2CO(g), k_(p)=63` atm at 100 K. If at equilibrium `p_(CO)=10p_(CO_(2)) ` then the total pressure of the gases at equilibrium is

A

`6*3` atm

B

`6*93` atm

C

`0*63 `atm

D

`0*693` atm

Text Solution

Verified by Experts

The correct Answer is:
B
`C(s) +CO_(2) (g) hArr 2 CO (g)`
`K_(p)=(p^(2) CO)/p_(CO_(2)) or 63 = ((10p_(CO_(2))))/(p_(CO_(2)))`
or `p_(CO_(2)) = 63/100 = 0.63 " atm"`
` p_(CO)= 10p_(CO_(2))= 10 xx 0.63 " atm " =6.3 " atm"`
` :. p_("total")= p_(CO_(2)) + p_(CO) = 0.63 + 6.3 = 6.93 " atm"`
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