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At equilibrium of the reaction , N(2)O...

At equilibrium of the reaction ,
`N_(2)O_(4)(g) hArr 2NO_(2)(g)`
the observed molecular weight of `N_92)O_(4)` is 80g `mol^(-1)` at 350K. The percentage dissociation of `N_(2)O_(4)(g)` at 350K is

A

0.1

B

0.15

C

0.2

D

0.18

Text Solution

Verified by Experts

The correct Answer is:
B
For the given dissociation reaction ,
`alpha =(D-d)/d = (M_(t)-M_(o))/(M_(o))=(92 xx80)/80 xx 100 = 15%`
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