Match the following species with the corresponding conjugate acid
`{:(,"Species",,,"Conjugate acid"),((i) ,NH_(3),,(a),CO_(3)^(2-)),((ii),HCO_(3)^(-),,(b),NH_(4)^(+)),((iii),H_(2)O,,(c),H_(3)O^(+)),((iv),HSO_(4)^(-),,(d),H_(2)SO_(4)),(,,,(e),H_(2)CO_(3)):}`

Explanation

To solve the problem of matching the given species with their corresponding conjugate acids, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Species and Their Conjugate Acids**:
- A conjugate acid is formed when a base accepts a proton (H⁺).
- We will analyze each species and determine what happens when they accept a proton.

2. **Match Each Species**:
- **(i) NH₃ (Ammonia)**:
- When NH₃ accepts a proton (H⁺), it becomes NH₄⁺ (Ammonium ion).
- **Match: (i) NH₃ → (b) NH₄⁺**.

- **(ii) HCO₃⁻ (Bicarbonate)**:
- When HCO₃⁻ accepts a proton, it becomes H₂CO₃ (Carbonic acid).
- **Match: (ii) HCO₃⁻ → (e) H₂CO₃**.

- **(iii) H₂O (Water)**:
- When H₂O accepts a proton, it becomes H₃O⁺ (Hydronium ion).
- **Match: (iii) H₂O → (c) H₃O⁺**.

- **(iv) HSO₄⁻ (Hydrogen sulfate)**:
- When HSO₄⁻ accepts a proton, it becomes H₂SO₄ (Sulfuric acid).
- **Match: (iv) HSO₄⁻ → (d) H₂SO₄**.

3. **Final Matching**:
- Now we can summarize the matches:
- (i) NH₃ → (b) NH₄⁺
- (ii) HCO₃⁻ → (e) H₂CO₃
- (iii) H₂O → (c) H₃O⁺
- (iv) HSO₄⁻ → (d) H₂SO₄

### Final Answer:
- (i) NH₃ → (b) NH₄⁺
- (ii) HCO₃⁻ → (e) H₂CO₃
- (iii) H₂O → (c) H₃O⁺
- (iv) HSO₄⁻ → (d) H₂SO₄