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The percentage of pyridine (C(5)H(5)N) t...

The percentage of pyridine `(C_(5)H_(5)N)` that forms pyridinium ion `(C_(5)H_(5)N^(+)H)` in a 0.10 M aqueous pyridine solution (`K_(b)` for `C_(5)H_(5)N=1.7xx10^(-9)`) is

A

0.0077

B

0.016

C

6.0E-5

D

0.00013

Text Solution

Verified by Experts

The correct Answer is:
D
Pyridine is a weak base. In aqueous solution, it ionizes as
`{:(,C_(5)H_(5)N+H_(2)O hArr C_(5)H_(5)overset(+)NH+OH^(-)),("Initial conc."," "c " " 0 " "0),("At. eqm." ,C(1-alpha)" " calpha " "calpha),(,K_(b) ~=C alpha^(2) " "("By Ostwald's dilution law")):}`
`alpha = sqrt((K_(b))/(C))=sqrt((1.7xx10^(-9))/(01))=sqrt(1.7xx10^(-8))=13.10^(-4)`
`: .` % disssociation (i.e. , % that forms `C_(5)H_(5)overset(+)NH` ion) `=1.3xx10^(-4)xx100=0.013 %`
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