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Ionisation constant of CH(3)COOH is 1.7x...

Ionisation constant of `CH_(3)COOH` is `1.7xx10^(-5)` and concentration of `H^(+)ions` is `3.4xx10^(-4)`. Then, find out initial concentration of `CH_(3)COOH` molecules.

A

`3.4xx10^(-4)`

B

`3.4xx10^(-3)`

C

`6.8xx10^(-3)`

D

`1.7xx10^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(,XH_(3)CO OH" " hArr" " CH_(3)CO O^(-) + H^(+)),("Initial conc."," "a),("At. eqm.",(a-3.4 xx 10^(-4)) " "3.4xx10^(-4)" " 3.4 xx 10^(-4)):}`
`((3.4xx10^(-4))(3.4xx10^(-4)))/((a-3.4 xx 10^(-4))) = 1.7 xx 10^(-5) ` (Given)
or, `(a-3.4xx10^(4))=((3.4xx10^(-4))^(2))/(1.7xx10^(-5))=6.8xx10^(-3)`
or `a=6.8xx10^(-3)+3.4xx10^(-4)~~ 6.8 xx 10^(-3)`
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