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At 25^(@)C, the dissociation constant of...

At `25^(@)C`, the dissociation constant of a base. BOH is `1.0xx10^(-12)`. The concentration of hydroxyl ions in `0.01`M aqueous solution of the base would be

A

`1.0xx10^(-6) "mol " L^(-1)`

B

`1.0xx10^(-7) "mol " L^(-1)`

C

`2.0xx10^(-6) "mol " L^(-1)`

D

`1.0xx10^(-5) "mol " L^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`BOH hArr B^(+) + OH^(-)`
`K=([B^(+)][OH^(-)])/([BOH]) = ([OH^(-)]^(2))/([BOH])`
or `[OH^(-)]=sqrt(K[BOH])=sqrt(10^(-12)(0.01))`
`=10^(-7)"mol" L^(-1)`
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