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For a concentrated solution of a weak e...

For a concentrated solution of a weak electrolyte, `A_(x) B_(y)` of concentration 'C', the degree of dissociation `alpha` is given by

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The correct Answer is:
C

`{:(,A_(x)B_(y),hArrxA^(y+),+yB^(x-)),("Initial",c," "0," "0),("At eqm.",c"("1-alpha")",xcalpha,ycalpha):}`
`K_(eq)=((xcalpha)^(x)(ycalpha)^(y))/(c(1-alpha))~~((xcalpha)^(x)(ycalpha)^(y))/(c)`
`" "("Taking"1-alpha~~1)`
`or" "K_(eq)=(x^(x)y^(y)c^(x+y)alpha^(x+y))/(c)=x^(x)y^(y)c^(x+y-1)alpha^(x+y)`
`:.alpha=(K_(eq)//c^(x+y-1)x^(x)y^(y))^(1//(x+y))`
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