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Which one of the following behaves as Le...

Which one of the following behaves as Lewis base as well as Bronsted-Lowry base ?

A

Carbonium ion

B

Carbanion

C

Carbenium ion

D

All of these

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The correct Answer is:
To determine which of the given options behaves as both a Lewis base and a Bronsted-Lowry base, we need to analyze each option based on their definitions. ### Step 1: Understand the Definitions - **Lewis Base**: A Lewis base is defined as a species that is electron-rich and can donate a pair of electrons to another species. - **Bronsted-Lowry Base**: A Bronsted-Lowry base is defined as a species that can accept a proton (H⁺). ### Step 2: Analyze Each Option 1. **Option A: Carbonium Ion (C⁺)** - Structure: R₃C⁺ (where R represents alkyl groups) - Analysis: Carbonium ions have a positive charge, indicating electron deficiency. They cannot donate electrons, so they do not qualify as Lewis bases. They can accept protons, so they can be Bronsted-Lowry bases, but they do not meet both criteria. 2. **Option B: Carbanion (C⁻)** - Structure: R₃C⁻ - Analysis: Carbanions are negatively charged and have a lone pair of electrons, making them electron-rich. They can donate this lone pair, qualifying them as Lewis bases. Additionally, they can accept a proton to form a neutral molecule (e.g., CH₄), qualifying them as Bronsted-Lowry bases. Thus, carbanions behave as both. 3. **Option C: Carbenium Ion (C⁺)** - Structure: R₃C⁺ (similar to carbonium ion) - Analysis: Carbenium ions are also positively charged and thus electron-deficient. They cannot donate electrons, so they do not qualify as Lewis bases. They can accept protons, making them Bronsted-Lowry bases, but again, they do not meet both criteria. 4. **Option D: All of These** - Analysis: Since only the carbanion qualifies as both a Lewis base and a Bronsted-Lowry base, this option is incorrect. ### Conclusion Based on the analysis, the correct answer is **Option B: Carbanion (C⁻)**, as it behaves as both a Lewis base and a Bronsted-Lowry base. ---

To determine which of the given options behaves as both a Lewis base and a Bronsted-Lowry base, we need to analyze each option based on their definitions. ### Step 1: Understand the Definitions - **Lewis Base**: A Lewis base is defined as a species that is electron-rich and can donate a pair of electrons to another species. - **Bronsted-Lowry Base**: A Bronsted-Lowry base is defined as a species that can accept a proton (H⁺). ### Step 2: Analyze Each Option 1. **Option A: Carbonium Ion (C⁺)** ...
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PRADEEP-EQUILIBRIUM-Competition Focus (I. Multiple Choice Questions(with one correct Answer)) (II. Various concepts of Acids and Bases, their dissociation constants and strength)
  1. Which one of the following is the correct statement ?

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  2. Which one of the following species cannot act as both Bronsted acid a...

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  3. Which one of the following behaves as Lewis base as well as Bronsted-L...

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  4. Mg^(2+) is .......... Than Al^(3+)

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  5. Sulphanilic acid is a/an:

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  6. Choose the correct order arranged in decreasing order of basicity

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  7. Which one of the following ionic species has the greatest proton affin...

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  8. The correct order of increasing basicity of the given conjugate bases ...

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  9. Three reactions involving H(2)PO(4)^(-) are given below I. H(3)PO(4...

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  10. Which one of the following molecules hydrides acts as a Lewis acid ?

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  11. Which of the of the following fluoro -compouds is most likely to beahv...

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  12. Which of the following statements about HCO(3)^(-) are correct ? 1. ...

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  13. Which of the following is least likely to behave as Lewis acid?

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  14. The correct order of increasing [H3O^+] in the following aqueous solut...

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  15. Strongest conjugate base is

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  16. The strongest base of the following species is

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  17. In HS^(-), I^(-), R-NH(2), NH(3) order of proton accepting tendency wi...

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  18. In which cases, the order of acidic strength is not correct ?

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  19. In aqueous solution the ionization constants for carbonic acid are: ...

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  20. The correct order of decreasing acidic nature of H(2)O, ROH, CH -= CH ...

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