The `K_(sp)` of `Ag_(2)CrO_(4)` is `1.1xx10^(-12)` at `298K`. The solubility (in mol/L) of `Ag_(2)CrO_(4)` in a `0.1 M AgNO_(3)` solution is

Options

A. `1.1xx10^(-11)`
B. `1.1xx10^(-10)`
C. `1.1xx10^(-12)`
D. `1.1xx10^(-9)`

Answer

B

Explanation

`{:(Ag_(2)CrO_(4),hArr,2"Ag"^(+),+,CrO_(4)^(-)),(s,,2s+0.1,,s),(,,(0.1 "from AgNO"_(3)),,),(,,~= 0.1 M,,),(,,"(as s is negligible in comparison to 0.1)",,),(,,,,):}`
`K_(sp)=[Ag^(+)]^(2)[CrO_(4)^(2-)]`
`1.1xx10^(-12)= (0.1)^(2)xxs or s=1.1xx10^(-10)M`