Concentration of the `Ag^(+)` ions in a saturated solution of `Ag_(2)CO_(2)O_(4)` is `2.2xx10^(-4) mol L^(-1)` Solubility product of `Ag_(2)C_(2)O_(4)` is:

Options

A. `2.42xx10^(-8)`
B. `2.66xx10^(-12)`
C. `4.5xx10^(-11)`
D. `5.3xx10^(-12)`

Answer

D

Explanation

`Ag_(2)C_(2)O_(4)(s) hArr 2Ag^(+)(aq)+C_(2)O_(4)^(2-)(aq)`,
`K_(sp)=[Ag^(+)]^(2)[C_(2)O_(4)^(2-)]`
Given `[Ag^(+)]=2.2xx10^(-4) "mol"L^(-1)`
`:. [C_(2)O_(4)^(2-)]=(2.2xx10^(-4))/(2)=1.1xx10^(-4)M`
`:. K_(sp)=(2.2xx10^(-4))^(2) (1.1xx10^(-4))`
`=5.324xx10^(-12)`