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The pK(a) of a weak acid (HA) is 4.5. Th...

The `pK_(a)` of a weak acid `(HA)` is `4.5`. The `pOH` of an aqueous buffered solution of `HA` in which `50%` of the acid is ionized is:

A

`7.0`

B

`4.5`

C

`2.5`

D

`9.5`

Text Solution

Verified by Experts

The correct Answer is:
D
When HA is 50% ionized , [HA] = `[A^(-)]`
`pH = pK_(a)+log .([A^(-)])/([HA])=pK_(a)=4.5 ` (Given)
`pOH = 14- pH = 14 - 4.5 = 9.5.
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