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What is [H^(+)] in mol//L of a solution ...

What is `[H^(+)]` in `mol//L` of a solution that is `0.20 M` in `CH_(3)COONa` and `0.1 M` in `CH_(3)COOH`? `K_(a)` for `CH_(3)COOH` is `1.8xx10^(-5)`?

A

`9.0xx10^(-6)`

B

`3.5xx10^(-4)`

C

`1.1xx 10^(-5)`

D

`1.8xx10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
A
The given solution is an acidic buffer. Hence, its pH will be
`pH = pK_(a) +log. (["Salt"])/(["Acid"])`
`=-log.(1.8xx10^(-5))+log.(0.20)/(0.10)`
or `-log(h^(+)]=log.(2)/(1.8xx10^(-5))`
or `log.(1)/([H^(+)])=log.(2)/(1.8xx10^(-5))`
or `[H^(+)]=(1.8xx10^(-5))/(2) = 0.9xx10^(-5)M`
`=9xx10^(-6)M`
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