`NaHCO_(3)` and NaOH cannot exist in a solution because of

Options

A. common ion effect due to common `Na^(+)` ions
B. redox reaction occurring between the two
C. neutralization reaction occurring between the two
D. different solubilities of the two in water.

Explanation

To solve the question of why NaHCO₃ (sodium bicarbonate) and NaOH (sodium hydroxide) cannot exist in a solution together, we can follow these steps:

### Step 1: Understanding the Compounds
- **NaHCO₃** is a weak acid (bicarbonate) that can donate a proton (H⁺).
- **NaOH** is a strong base that can accept a proton and produce hydroxide ions (OH⁻).

### Step 2: Reaction Between NaHCO₃ and NaOH
- When NaOH is added to a solution containing NaHCO₃, the hydroxide ions (OH⁻) from NaOH will react with the acidic hydrogen (H⁺) from NaHCO₃.
- This reaction can be represented as:
\[ \text{NaHCO}_3 + \text{NaOH} \rightarrow \text{Na}_2\text{CO}_3 + \text{H}_2\text{O} \]
- Here, NaHCO₃ is neutralized by NaOH, resulting in the formation of sodium carbonate (Na₂CO₃) and water (H₂O).

### Step 3: Conclusion
- Since NaHCO₃ can be neutralized by NaOH, they cannot coexist in the same solution without undergoing a reaction. The presence of NaOH will lead to the complete conversion of NaHCO₃ to Na₂CO₃, thus preventing both from being present simultaneously.

### Final Answer
- Therefore, NaHCO₃ and NaOH cannot exist in a solution together due to a **neutralization reaction occurring between the two**.

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