`{:(,"Column I",,"Column II"),((A),"Solubility of "Hg_(2)Cl_(2) "in" 0.1 " M NaCl solution".,(p),10K_(sp)),((B),"Solubility of "PbI_(2) " in 0.01 M KI solution",(q),100K_(sp)),((C),"Solubility of "Ag_(2)CrO_(4) "in 0.25 M" K_(2)CrO_(4) "solution".,(r),10000K_(sp)),((D),"Solubility of calcium oxalate in 0.1 M oxalic acid aolution.",(s),sqrt(K_(sp))):}`

Options

A. A-q, B-r, C-s, D-p
B. A-r, B-q, C-p, D-s
C. A-q, B-p, C-s, D-r
D. A-p, B-r, C-s, D-q

Answer

A

Explanation

A. `Hg_(2)Cl_(2) hArr Hg_(2)^(2+) + 2 Cl^(-)`
`K_(sp)=[Hg_(2)^(2+)][Cl^(-)]^(2)=S (0.1 + 2 S)^(2) ~~ (0.1)^(2)S`
`:. S = 100 K_(sp)`
Br. `PbI_(2) hArr Pb^(2+) + 2 I^(-)`
`K_(sp) = [Pb^(2+)][I^(-)]^(2)=S (0.01 + 2S)^(2) ~~ S (0.01)^(2)`
` = 10^(-4)S`
`:. S = 10^(4) K_(sp)`
C. `Ag_(2)CeO_(4) hArr 2 Ag^(+) + CrO_(4)^(2-)`
`K_(sp) = [ Ag^(+)]^(2) [CrO_(4)^(2-)]`
`=(2S)^(2)(0.25+S) ~~ (2S)^(2) (0.25)`
or `S=sqrt(K_(sp))`
D. `CaC_(2)O_(4) hArr Ca^(2+) + C_(2)O_(4)^(2-)`
`K_(sp)=[Ca^(2+)][C_(2)O_(4)^(2-)]`
`=S(0.1+S)~~0.1S or S = 10 K_(sp)`