White phosphorus reacts with chlorine and the product hydrolyses in the presence of water. Calcualte the mass of HCl obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water.

Explanation

The chemical equations for the reactions in involved are :
`{:(,P_(4)+6Cl_(2) to 4PCl_(3)),(,underline(PCl_(3) + 3H_(2)O to H_(3) PO_(3)+3HCl]xx4),(,underset(4xx31=124 g)(P_(4))+ 6Cl_(2)+12H_(2)O to 4H_(3)PO_(3)+underset (12 xx 36.5g)(12HCl)):}`
Now, 124 g of white P give `HCl=12xx36.5g`
`:.` 62 g of white P will give `HCl=(12xx36.5)/(124)xx62=219g`