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On heating lead (II) nitrate gives a bro...

On heating lead (II) nitrate gives a brown gas " A". The gas " A" on cooling changes to colourless solid "B" . Solid B on heating with NO changes to a blue solid 'C . Identify ' A', 'B' and' C and also write reactions involved and draw the structures of 'B' and 'C' .

Text Solution

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(i) Since lead (II) nitrate on heating gives a brown gas 'A' therefore, gas 'A' must be nitrogen dioxide `(NO_(2))`.
`{:underset("Lead (II) nitrate")(2Pb(NO_(3))_(2))overset(Delta,673K)to2PbO+underset("Brown gas (A)")(4NO_(2))+O_(2):}`
(ii) The brown gas 'A' on cooling dimerises to give a colourless solid 'B' therefore 'B' must be `N_(2)O_(4)` (dinitrogen tetroxide).
`{:2NO_(2)underset("On heating")overset("On cooling")hArrunderset("Colourless solid (B)")(N_(2)O_(4))`
(iii) Since colourles solid 'B' on heating with NO, gives a blue solid 'C' therefore 'C' must be dinitrogen trioxide.
`{:2NO+underset("Colourless solid (B)")(N_(2)O_(4))tounderset("Blue solid (C))(2N_(2)O_(3)):}`
Thus, `A=NO_(2),B=N_(2)O_(4)andC=N_(2)O_(3)`.
For structures,
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