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Calculate the degree of dissociation (al...

Calculate the degree of dissociation `(alpha)` of acetic acid if its molar conductivity `(^^_(m))` is 39.05 `S cm^(2) mol^(-1)`
Given `lamda^(@) (H^(+)) = 349.6 cm^(2) mol^(-1) and lamda^(2) (CH_(3)COO^(-)) = 40.9 S cm^(2) mol^(-1)`

Text Solution

Verified by Experts

`alpha=(wedge_(m))/(wedge_(m)^(@))`
`wedge_(m)^(@)(CH_(3)COOH)=lamda^(@)(CH_(3)COO^(-))+lamda^(@)(H^(+))=40.9+349.6=390.5" S "cm^(2)mol^(-1)`
`wedge_(m)=39.05" S "cm^(2)mol^(-1)`
`thereforealpha=(39.05)/(390.5)=0.1`
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