If the molar conductivities at infinite dilution of NaCl, HCl and `CH_(3)COONa(NaAc)` are 126.4, 425.9 and 91.0 S `cm^(2)mol^(-1)` respectively, what will be that of acetic acid (Hac)?

Explanation

To find the molar conductivity at infinite dilution of acetic acid (HAc), we can use the known molar conductivities of NaCl, HCl, and CH₃COONa (sodium acetate). We will apply the principle of additive molar conductivities.

### Step-by-Step Solution:

1. **Write the equations for molar conductivities**:
- For HCl:
\[
\Lambda^\circ_{\text{HCl}} = \Lambda^\circ_{\text{H}^+} + \Lambda^\circ_{\text{Cl}^-}
...