How many hours does it take to reduce 3 mol of `Fe^(3+)` to `Fe^(2+)` with 2.0 A current ? ( F= 96500 C)

Answer

40.2 hrs

Explanation

`Fe^(3+)+e^(-)toFe^(2+)` i.e., 1 mol requires 1F. `therefore3` moles will require=3F=`3xx96500C`
`t=Q//I=(3xx96500)//2.0=144750s=40.2`hrs.