The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 `Omega`. Calculate the equivalent conductance of the solution if the electrodes in the cell were 2 cm part and each had an area of 3.5 sq. cm.

Answer

`23.32ohm^(-1)cm^(2)eq^(-1)`

Explanation

`kappa=Gxx(l)/(a)=(1)/(R)xx(l)/(a)=(1)/(245Omega)xx(2cm)/(3.5cm^(2))`
`wedge_(eq)=kappaxx(1000)/("Normality")=((1)/(245)xx(2)/(3.5)Omega^(-1)cm^(-1))xx(1000cm^(3)L^(-1))/(0.1molL^(-1))=23.32Omega^(-1)cm^(2)eq^(-1)`