A cell with `N//50` KCl solution offered a resistance of 550 ohm at 298 K. The specific conductance of `N//50` KCl at 298 K is 0.002768 `ohm^(-1)cm^(-1)`. When this cell is filled with `N//10 ZnSO_(4)` solution, it offered a resistance of 72.18 ohm at 298 K. Find the cell constant and molar conductance of `ZnSO_(4)` solution at 298 K.

Answer

1.5224 `cm^(-1),421.8ohm^(-1)cm^(2)mol^(-1)`

Explanation

`(N)/(10)ZnSO_(4)" sol"=(M)/(20)ZnSO_(4)" sol. And "wedge_(m)=kappaxx(1000)/("Molarity")`.