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A potential difference of 20 V applied t...

A potential difference of 20 V applied to the ends of a column of 0.1 M `AgNO_(3)` solution 4 cm in diameter and 12 cm in length gave a current of 0.20 amperes . Calculate
(i) conductivity and
(ii) molar conductance of the solution .

Text Solution

Verified by Experts

The correct Answer is:
`9.55xx10^(-3)" S "cm^(-1),95.5" S "cm^(2)mol^(-1)`
By Ohm's law, `R=(E)/(I)=(20V)/(0.20A)=100VA^(-1)=100Omega`
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