The molar conductivity of a 1.5 M solution of an electrolyte is found to be `138.9 S cm^(2) mol^(-1)` . Calculate the conductivity of this solution.

Answer

0.208 S `cm^(-1)`

Explanation

`wedge_(m)=kappaxx(1000)/("Molarity"),i.e.,138.9" S "cm^(2)mol^(-1)=kappaxx(1000cm^(3)L^(-1))/(1.5" mol "L^(-1))` or `kappa=0.208" S "cm^(-1)`.