The measured resistance of a conductance cell containing `7.5xx10^(-3)M` solution of KCl at `25^(@)C` was 1005 ohms. Calculate (a) specific conductance (b) molar conductance of the solution. Cell constant=1.25 `cm^(-1)`.

Explanation

To solve the problem, we will calculate the specific conductance and molar conductance of the KCl solution step by step.

### Given Data:
- Resistance (R) = 1005 ohms
- Concentration (C) = \(7.5 \times 10^{-3} \, M\)
- Cell constant (k) = 1.25 cm\(^{-1}\)

### Step 1: Calculate Specific Conductance (κ)
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