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What will be the molar conductivity of Al 3+ ions at infinite dilution if molar conductivity of `Al^(2) (SO_(4))_(3)` is 858 S `cm^(2)` `"mol" ^(-1)` and ionic conductance of `SO_(4)^(2-)` is 160 S `cm^(2) "mol" ^(-1)` at infinite dilution ?

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The correct Answer is:
189 S `cm^(2)mol^(-1)`
`wedge_(m)^(@)[Al_(2)(SO_(4))_(3)]=2lamda_(m)^(@)(Al^(3+))+3lamda_(m)^(@)(SO_(4)^(2-))`
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