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Conductivity of saturated solution of Ba...

Conductivity of saturated solution of `BaSO_(4)" at 315 K is "3.648 xx 10^(-6)" ohm"^(-1)" cm"^(-1)` and that of water is `1.25 xx10^(-6)" ohm"^(-1)" cm"^(-1)`. Ionic conductance of `Ba^(2+) and SO_(4)^(2-)" are 110 and 136.6 ohm"^(-1)" cm"^(2)" mol"^(-1)` respectively. Calculate the solubility of `BaSO_(4)` in g/L.

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The correct Answer is:
`2.266xx10^(-3)gL^(-1)`
`kappa(BaSO_(4))=kappa("solution")-kappa("water")." solubility"=(kappaxx1000)/(wedge_(m)^(@))=((3.648-1.250)10^(-6)xx1000)/((110+136.6))xx233" g "L^(-1)`.
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