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A voltaic cell is set up at 25^(@)Cwith ...

A voltaic cell is set up at `25^(@)C`with the following half cells :
`Al^(3+)`(0.001 M) and `Ni^(2+)`(0.50 M)
Write the equation for the reaction when the cell generates the electric current. Also determine the cell potential (Given `E_(Ni^(2+)//Ni)^(@)=-0.25 V, E_(Al^(3+)//Al)^(@)=-1.66 V)`.

Text Solution

Verified by Experts

The correct Answer is:
`1.46V`

`Ni^(2+)+2e^(-)toNi,E_(Ni^(2+)//Ni)=0.25-(0.0591)/(2)"log"(1)/(0.50)=-0.259V`
`Al^(3)+3e^(-)toAl,E_(Al^(3+)//Al)=-1.66-(0.0591)/(3)"log"(1)/(10^(-3))=-1.719V`
For EMF to be +ve, oxidation should occur on Al-electrode. Cell reaction: `2Al+3Ni^(2+)to2Al^(3+)+3Ni`
`E_(cell)=-0.259+1.719V=1.46V`
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