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Calculate the emf of the following cell ...

Calculate the emf of the following cell at `298K`:
`Fe(s)|Fe^(2+)(0.001M)||H^+(1M)|H_2(g)(1"bar"),Pt(s)` (Given`E_("Cell")^@=+0.44V)`

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Verified by Experts

The correct Answer is:
0.53 V
`Fe+2H^(+)toFe^(2+)+H_(2)`,
`E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Fe^(2+)])/([H^(+)]^(2))=0.44-(0.0591)/(2)"log"(0.001)/((1)^(2))`
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