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Calculate the equilibrium constant for t...

Calculate the equilibrium constant for the reaction at 298K.
`Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s)`
Given, `E_(Zn^(2+)//Zn)^(@) =- 0.76V` and `E_(Cu^(2+)//Cu)^(@) = +0.34 V`

Text Solution

Verified by Experts

The correct Answer is:
`2.121xx10^(37)`
`E_(cell)^(@)=E_(Cu^(2+)//Cu)^(@)-E_(Zn^(2+)//Zn)^(@)=0.34-(-0.0763)V=1.103V`.
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