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Calculate the equilibrium constant for the reaction, `2Fe^(3+)+3I^(-)hArr2Fe^(2+)+I_(3)^(-)`, the standard reduction potentials in acidic conditions are 0.77V and 0.54V respectively for `Fe^(3+)//Fe^(2+)` and `I_(3)^(-)//I^(-)` couples.

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The correct Answer is:
`6.073xx10^(7)`
Cell is `I^(-)|I_(3)^(-)||Fe^(3+)|Fe^(2+),E_(cell)^(@)=0.77-0.54=0.23V,n=2`
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Calculate the euilibrium constant for the reaction, 2Fe^(3+) + 3I^(-) hArr 2Fe^(2+) + I_(3)^(-) . The standard reduction potential in acidic conditions are 0.77 V and 0.54 V respectivelu for Fe^(3+)//Fe^(2+) and I_(3)^(-)//I^(-) couples.

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