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Calculate the standard cell potential of...

Calculate the standard cell potential of the galvanic cell in which the following reaction takes place:
`2Cr(s)+3Cd^(2+)(aq)to2Cr^(3+)(aq)+3Cd(s)`
Also calcuate the `triangle_(r)G^(ɵ)` value of the reaction
(given `E_(cr^(3+)//Cr)^(ɵ)=-0.74V,E_(Cd^(3+)//Cd)^(ɵ)=-0.40V` and `F=96500Cmol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
`+0.34V,-196.86kJ" "mol^(-1)`
`Cr(s)|Cr^(3+)(aq)||Cd^(2+)(aq)|Cd(s)`
`2Crto2Cr^(3+)+6e^(-)` or `3Cd^(2+)+6e^(-)to3Cd`. Hence, n=6
`E_(cell)^(@)=-0.40-(-0.74)=+0.34V,Delta_(r)G^(@)=-nFE_(cell)^(@)`
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